Given a string s consists of upper/lower-case alphabets and empty space characters
' ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s =
return
Given s =
"Hello World",return
5.
Solution:
public class Solution {
public int lengthOfLastWord(String s) {
int pos=0;
for(int i=s.length()-1;i>=0;i--)
{
if(s.charAt(i)!=' ')
pos++;
else if(pos>0 && s.charAt(i)==' ')
break;
}
return pos;
}
}
Discussion:I first attempt was from the beginning of the string, but failed to consider the situation when "a ". Then I tried iterate from tail of the string then succeeded.
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