Compare Version Numbers

Problem:

Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

Analysis:

Use string.split method. Split the string into two arrays by '.'.

Solution:

1:  public static int CompareVersion(string version1, string version2)  
2:      {  
3:        string[] v1 = version1.Split('.');  
4:        string[] v2 = version2.Split('.');  
5:        int longest = v1.Length > v2.Length ? v1.Length : v2.Length;  
6:        for(int i=0;i<longest;i++)  
7:        {  
8:          int ver1 = i < v1.Length ? int.Parse(v1[i]) : 0;  
9:          int ver2 = i < v2.Length ? int.Parse(v2[i]) : 0;  
10:          if (ver1 > ver2) return 1;  
11:          if (ver1 < ver2) return -1;  
12:        }  
13:        return 0;  
14:      }